Contains the point (-1, 2) and is parallel tox – 2y = -3

Answer:see explanationStep-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )Rearrange x - 2y = - 3 into this formSubtract x from both sides - 2y = - x - 3 ( divide all terms by - 2 )y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{3}{2}[/tex] ← in slope- intercept formwith m = [tex]\frac{1}{2}[/tex]• Parallel lines have equal slopes, thusy = [tex]\frac{1}{2}[/tex] x + c ← is the partial equationTo find c substitute (- 1, 2) into the partial equation2 = - [tex]\frac{1}{2}[/tex] + c ⇒ c = 2 + [tex]\frac{1}{2}[/tex] = [tex]\frac{5}{2}[/tex]y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{2}[/tex] ← in slope- intercept formMultiply through by 22y = x + 5 ( subtract 2y from both sides )0 = x - 2y + 5 ( subtract 5 from both sides )- 5 = x - 2y, thusx - 2y = - 5 ← in standard form